Skip to content

Categories:

範例:彈力的應用(僵硬程度)[103學測]

科學家為了研究人類步伐與姿勢以了解肢體如何隨著感官以及週遭環境而調適。使用如圖(a)的簡化模型,假設人體質量集中於O處,下肢為一長度為L的彈性體,踏下臺階時腳底對著地面施力,下肢受到地面之鉛直反作用力F,所以長度會有所改變,設其絕對值為ΔL,則F與ΔL的比值F/ΔL,可用以代表人腳垂直踩踏較低地面時下肢的僵硬程度,S愈大代表踩踏時下肢愈僵硬。圖(b)為甲受測者踏下固定落差的臺階時,所受之F與對應之ΔL的實驗數據。從圖(b)的實驗數據研判,甲受測者垂直踩踏臺階時的「僵硬程度S」約是多少N/m?
(A) 4.0×10-5 (B) 6.5×10-1 (C) 6.5×102 (D) 1.0×103 (E) 2.4×104

相關文章:

Posted in 歷屆學測(推甄)考題, 歷屆學測試題, 牛頓運動定律.

Tagged with , , .


0 Responses

Stay in touch with the conversation, subscribe to the RSS feed for comments on this post.

You must be logged in to post a comment.



63 visitors online now
10 guests, 10 bots, 43 members
All time: 479 at 08-18-2020 08:10 pm UTC
Max visitors today: 106 at 12:00 am UTC
This month: 145 at 11-03-2024 07:36 pm UTC
This year: 259 at 08-23-2024 08:56 pm UTC