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範例:摩擦力的動力學(二)方向的判斷[91指考]

一水平輸送帶恆以等速度v沿+x方向移動,在時刻t=0時,將一質量為m的箱子以水平速度u=0置於輸送帶上,如圖所示,若箱子與輸送帶之間的靜摩擦係數為μs,動摩擦係數為μk,重力加速度為g,則下列有關此箱子的敘述,何者正確? (A)摩擦力對箱子所做的總功為-0.5mv2 (B)t=v/(μkg)時,箱子的速度等於輸送帶的速度 (C)在時刻t=0時,箱子所受的淨力為μs mg,向+x方向 (D)在時刻t=0時,箱子所受的淨力為μk mg,向x方向 (E)當箱子的速度等於v時,箱子所受的摩擦力為μs mg,向+x方向.[91指定考]


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Posted in 歷屆物理考題, 牛頓第二運動定律.

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