Skip to content

Categories:

範例:摩擦力的動力學(二)方向的判斷[91指考]

一水平輸送帶恆以等速度v沿+x方向移動,在時刻t=0時,將一質量為m的箱子以水平速度u=0置於輸送帶上,如圖所示,若箱子與輸送帶之間的靜摩擦係數為μs,動摩擦係數為μk,重力加速度為g,則下列有關此箱子的敘述,何者正確? (A)摩擦力對箱子所做的總功為-0.5mv2 (B)t=v/(μkg)時,箱子的速度等於輸送帶的速度 (C)在時刻t=0時,箱子所受的淨力為μs mg,向+x方向 (D)在時刻t=0時,箱子所受的淨力為μk mg,向x方向 (E)當箱子的速度等於v時,箱子所受的摩擦力為μs mg,向+x方向.[91指定考]


[另啟瀏覽]

相關文章:

Posted in 歷屆物理考題, 牛頓第二運動定律.

Tagged with , , , , .


3 Responses

Stay in touch with the conversation, subscribe to the RSS feed for comments on this post.

  1. Down ShiRt says

    “I commonly really don’t publish in Blogs but your blog pressured me to, amazing perform.! beautiful …”

  2. Noelia Goad says

    You really are a extremely intelligent person!

  3. tchibo gutschein says

    nice!

You must be logged in to post a comment.



41 visitors online now
9 guests, 9 bots, 23 members
All time: 479 at 08-18-2020 08:10 pm UTC
Max visitors today: 58 at 10:32 am UTC
This month: 145 at 11-03-2024 07:36 pm UTC
This year: 259 at 08-23-2024 08:56 pm UTC