Skip to content

Categories:

範例:牛頓第二運動定律與視重

(1)a=0.20 m/s2之等加速度垂直上升的電梯內,有一乘客,其質量為 m=50kg,試求乘客施於電梯地板之力為多少牛頓?(g=9.8 m/s2)

(2)若電梯向下以加速度a=0.20 m/s2垂直下降,則又如何?

(3)若電梯的鋼索斷了,電梯以重力加速度g自由落下時,又如何?


[以powercam player瀏覽]

相關文章:

Posted in 牛頓第二運動定律.

Tagged with , .


0 Responses

Stay in touch with the conversation, subscribe to the RSS feed for comments on this post.

You must be logged in to post a comment.