一石自高樓頂鉛直上拋經t1秒落地,若以同速率鉛直下拋經t2秒落地,則: (A)初速Vo=g(t1+t2)/2 (B)初速為g(t1-t2)/2 (C)樓高h=t1t2/2g (D)樓高g t1t2/2 (E)石子離地最大高度為g(t1+t2)2/2。
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一石自高樓頂鉛直上拋經t1秒落地,若以同速率鉛直下拋經t2秒落地,則: (A)初速Vo=g(t1+t2)/2 (B)初速為g(t1-t2)/2 (C)樓高h=t1t2/2g (D)樓高g t1t2/2 (E)石子離地最大高度為g(t1+t2)2/2。
Posted in 等加速度.
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– 2010 年 08 月 09 日
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