如圖所示當F=10牛頓時,恰可使OA線偏離鉛直線30o,並維持平衡;若欲使OA線偏離鉛直線53o,且維持平衡,則F施力為多少牛頓?[88前中]
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如圖所示當F=10牛頓時,恰可使OA線偏離鉛直線30o,並維持平衡;若欲使OA線偏離鉛直線53o,且維持平衡,則F施力為多少牛頓?[88前中]
Posted in 合力=0.
Tagged with 前鎮高中段考, 合力=0, 拉密定理.
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By admin – 2010 年 09 月 14 日
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