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範例:牛頓第二運動定律與視重

(1)以a=0.20 m/s2之等加速度垂直上升的電梯內,有一乘客,其質量為 m=50kg,試求乘客施於電梯地板之力為多少牛頓?(g=9.8 m/s2)

(2)若電梯向下以加速度a=0.20 m/s2垂直下降,則又如何?

(3)若電梯的鋼索斷了,電梯以重力加速度g自由落下時,又如何?


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Posted in 牛頓第二運動定律.

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By admin – 2010 年 10 月 26 日

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